Saved Bookmarks
| 1. |
If the median of \(\frac{x}{6},\) \(\frac{x}{2},\) \(\frac{x}{4},\) \(\frac{3x}{5}\) and \(\frac{7x}{10}\) is 3, then the mean of the given observations is : (a) 2.5 (b) 3.06 (c) 2.16 (d) 2.66 |
|
Answer» (d) 2.66 Arranged in ascending order, the values are \(\frac{x}{6},\) \(\frac{x}{2},\) \(\frac{x}{4},\) \(\frac{3x}{5}\) and \(\frac{7x}{10}\) ∴ Median value = \((\frac{5+1}{2})\)th value = 3rd value = \(\frac{x}{2}\) Given \(\frac{x}{2}\) = 3 ⇒ x = 6 ∴ The values are \(\frac{6}{6},\) \(\frac{6}{4},\) \(\frac{6}{2},\) \(\frac{3\times6}{5},\) \(\frac{7\times6}{10},\) i.e., 1, 1.5, 3, 3.6 and 4.2 ∴ Mean = \(\frac{1+1.5+3+3.6+4.2}{5}\) = \(\frac{13.3}{5}\) = 2.66 |
|