1.

If the number of electrons (majority carrier) in a semiconductor is 5 X 10^20 m^-3 and μe is 0.135 mho, find the resistivity of the semiconductor.(a) 0.0926 Ωm(b) 0.0945 Ωm(c) 0.0912 Ωm(d) 0.0978 Ωm

Answer» Correct option is (a) 0.0926 Ωm

Explanation: We know, Conductivity, σ = ene μe

= 5 X 1.6 X 0.135 X 10 mho/m

= 10.8 mho/m

Resistivity = 1/σ

= 0.0926 Ωm.


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