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If the numbers (2n – 1), (3n + 2) and (6n – 1) are in AP, find the value of n and the numbers. |
Answer» Given: (2n – 1), (3n + 2) and (6n – 1) are in AP So, (3n + 2) – (2n – 1) = (6n – 1) – (3n + 2) (3n + 2) + (3n + 2) = 6n – 1 + 2n – 1 6n + 4 = 8n – 2 8n – 6n = 4 + 2 Or n = 3 Numbers are: 2 x 3 – 1 = 5 3 x 3 + 2 = 11 6 x 3 – 1 = 17 Answer: (5, 11, 17) are required numbers. |
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