If the periodic time of a pendulum whose length is 36.9 cm equals 1.22 seconds, how much gravitational acceleration is in the pendulum's region of existence?

If the periodic time of a pendulum whose length is 36.9 cm equals 1.22

1.	If the periodic time of a pendulum whose length is 36.9 cm equals 1.22 seconds, how much gravitational acceleration is in the pendulum's region of existence?
Answer» t=2pie√L/√gsobst²=4pie²l/gt=1.22 APPROXIMATELY t=1length (L) =36.9 approximately l= 371²=4(10)(37)/(G) 1=40(37)/gg=40(37)g=1480g=14.8

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If the periodic time of a pendulum whose length is 36.9 cm equals 1.22 seconds, how much gravitational acceleration is in the pendulum's region of existence?

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