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If the point A (0, 2) is equidistant from the points B (3, p) and C (p, 5) the length of AB. |
Answer» Coordinates of points are A(0, 2), B(3, p) and C(p, 5) Using distance formula = \(\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\) ⇒ AB = AC \(\sqrt{(3 - 0)^2 + (p - 2)^2}\) = \(\sqrt{(p - 0)^2 + (5 - 2)^2}\) On squaring both sides, we get (3 - 0)2 + (p - 2)2 = (p - )2 + (5 - 2)2 9 + p2 - 4p + = p2 + 9 - 4p = - 4 p = 1 AB = \(\sqrt{(3 - 0)^2 + (1 - 2)^2}\) = \(\sqrt{9 + 1}\) = \(\sqrt{10}\) units |
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