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If the radius of earth shrinks by 1.5% (massremaining same), then the value of gravitationalacceleration changes by(1) 2%(3) 3%(2) -2%(4) -3% |
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Answer» g = G M / R^2 as, R is decreased by 1.5% So, new Radius , R' = R - 0.015 R = 0.985R So, new g, g' = G M / (0.985R)^2 = 1.0306 G M/ R^2 So, change = 0.0306 % change = 3 % (approx) |
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