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If the rate constant for the disintegration of a radioactive nucleus is `lambda`. Therefore the probability, `P` of survival of a radioactive nucleus for one mean life isA. `e`B. ( b) `e^(2)`C. `e^(-1)`D. `e^(-2)` |
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Answer» Correct Answer - C Probability for survival `= (N)/(N_(0)) = e^(-lambda ul(t))` Now mean life period `= (1)/(lambda)` `:.` Probability `= e ^(-lambda xx (1)/(lambda)) = e^(-1)` |
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