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If the rate of a reaction is 5 at `10^(@)C ` then on increasing the temperature to `30^(@)C` , new rate isA. 20B. 10C. 50D. 40 |
Answer» Correct Answer - a For every `10^(@)` rise of temperature rate constant doubles . For `20^(@)` rise of temperature , rate constant becomes 4 times , i.e., `k_(2) = 4k_(1) = 4 xx 5 = 20.` |
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