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| 1. |
If the ratio of swimmer velocity to the river velocity is ‘2’, then the angle at which the swimmer swims with the water flow to cross the river in minimum time is |
| Answer» CORRECT option isAsinθThe correct option is A.Letdistance=dThe angle made with the upstream=θTherefore,90−θ=Angle made with the normal stream HENCE, Shortest Time METHOD:Time taken, t= VD Shortest distance method:Time taken = t'= vcos(90−θ)d = vsinθd THEREFORE, required ratio= t ′ t = vd sinθvd =sinθ | |