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If the ratio of the concentration of electron to that of holes in a semiconductor is `(7)/(5)` and the ratio of current is `(7)/(4)` then what is the ratio of their drift velocities ?A. `5//8`B. `4//5`C. `5//4`D. `4//7` |
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Answer» Correct Answer - C `I=n_(e) Av_(d)` `(I_(e))/(I_(h))=(n_(e)xx(v_(d))_(e))/(n_(h)xx(v_(d))_(h))` Here `(n_(e))/(n_(h))=7/5 xx((v_(d))_(e))/((v_(d))_(h))=(7)/(4)` `(7)/(4) = (7)/(5) xx((v_(d))_(e))/((v_(d))_(h))` `rArr ((v_(d))_(e))/((v_(d))_(g))=5/7xx7/4 =5/4` |
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