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If the ratio of the concentration of electron to that of holes in a semiconductor is `(7)/(5)` and the ratio of current is `(7)/(4)` then what is the ratio of their drift velocities ?A. `(5)/(8)`B. `(4)/(5)`C. `(5)/(4)`D. `(4)/(7)` |
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Answer» Correct Answer - C `I=n_(e)Av_(d)` `(I_(e))/(I_(n))=(n_(e)xx(v_(d))_(e))/(n_(h)xx(v_(d))_(h)) ` Here, `(n_(e))/(n_(h))=(7)/(5), (I_(e))/(I_(h))=(7)/(4)` `therefore (7)/(4)=(7)/(5)xx((v_(d))_(e))/((v_(d))_(h)) rArr ((v_(d))_(e))/((v_(d))_(h))=(5)/(7)xx(7)/(4)=(5)/(4)` |
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