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If the scalar projection of vector `xhati-hatj+hatk1` on vector `2hati-hatj+5hatk is 1/sqrt30`. The find the value of x. |
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Answer» Projection of `xhati-hatj+hatk "on" 2hati-hatj+5hatk= ((xhati-hatj+hatk).(2hati-hatj+5hatk))/(sqrt(4+1+25))` `(2x+1+5)/(sqrt10)` But, given `(2x+6)/(sqrt30)=1/sqrt30 Rightarrow 2x+6=1 or x=(-5)/2` |
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