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If the sound level in a room is increased from 50 dB to 60 dB, by what factor is the pressure amplitude increased ? |
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Answer» Correct Answer - A `beta_1=50dB, beta_2=60dB,` I_1=10^-7W/m^2, I_2=10^-6W/m^2` `[because beta=10log_10(I/I_0)` where `I_0=10^-12W/m^2]` Again, `I_2/I_1=(p_2/p_1)^2=(10^-6/10^-7)=10` `(where p=pressure amplitude) `:.(p_2/p_1)^2=10` `rarr P_2/P_1=sqrt10` |
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