If the speed of the wave shown in the figure is `330m//s` in the given medium then the equation of the wave propagating in the positive x-direction will be (all quantities are in M.K.S units)A. `y=0.05sin2pi(4000t-12.5x)`B. `y=0.05sin2pi(4000t-122.5x)`C. `y=0.05sin2pi(3300t-10x)`D. `y=0.05sin2pi(3300x-10t)`

If the speed of the wave shown in the figure is `330m//s` in the give

1.	If the speed of the wave shown in the figure is `330m//s` in the given medium then the equation of the wave propagating in the positive x-direction will be (all quantities are in M.K.S units)A. `y=0.05sin2pi(4000t-12.5x)`B. `y=0.05sin2pi(4000t-122.5x)`C. `y=0.05sin2pi(3300t-10x)`D. `y=0.05sin2pi(3300x-10t)`
Answer» Correct Answer - C Here `A=0.05m`,`(5lamda)/(2)=0.025implieslamda=0.1m` Now standard equation of wave `y=Asin(2pi)/(lamda)(vt-x)impliesy=0.5sin2pi(3300t-10x)`

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