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If the sum of n terms of an A.P. is 3n2 + 5n then which of its terms is 164? A. 26th B. 27th C. 28th D. none of these |
Answer» Here, Sn = 3n2 + 5n S1 = a1 = 3 + 5 = 8 S2 = a1 + a2 = 12 + 10 = 22 ⇒ a2 = S2 – S1 = 22 – 8 = 14 S3 = a1 + a2 + a3 = 27 + 15 = 42 ⇒a3 = S3 – S2 = 42 – 22 = 20 ∴ Given AP is 8, 14, 20, ..... Thus a = 8, d = 6 Given tm = 164. 164 = [a + (n –1)d] 164 = [(8) + (m –1)6] 164 = [8 + 6m – 6] 164 = [2 + 6m] 162 = 6m m = 162 / 6. ∴ m = 27. |
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