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If the sum of the distances of a point from two perpendicular lines ina plane is 1, then its locus isa square(b) a circlea straight line (d) two intersecting linesA. squareB. circleC. straight lineD. two intersecting lines |
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Answer» By the given conditions, we can take two perpendicular lines as `x` and `y` axes. If `(h,k)` is any point on the locus, then `|h|+|k|=1`. Therefore, the locus is `|x|+|y|=1`. This consist of a square of side `1`. Hence, the required locus is a square. |
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