1.

If the sum of three numbers in A.P. is 24 and their product is 440, find the numbers.

Answer»

Given : 

Sum of first three terms is 24 

To find : the first three terms of AP 

Assume the first three terms are a - d, a, a + d where a is the first term and d is the common difference 

So, 

Sum of first three terms is a - d + a + a + d = 24 

3a = 24 

a = 8 

Given that,

The product of three terms is 440 

So a3 - ad2 = 440 

Substituting a = 8 

83 - 8d2 = 440 

512 - 8d2 = 440 

72 = 8d2 

d = 3 or d = - 3 

Hence,

The given terms are a - d, a, a + d which is 5, 8, 11 or 11, 8, 5.



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