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If the sum of three numbers in A.P. is 24 and their product is 440, find the numbers. |
Answer» Given : Sum of first three terms is 24 To find : the first three terms of AP Assume the first three terms are a - d, a, a + d where a is the first term and d is the common difference So, Sum of first three terms is a - d + a + a + d = 24 3a = 24 a = 8 Given that, The product of three terms is 440 So a3 - ad2 = 440 Substituting a = 8 83 - 8d2 = 440 512 - 8d2 = 440 72 = 8d2 d = 3 or d = - 3 Hence, The given terms are a - d, a, a + d which is 5, 8, 11 or 11, 8, 5. |
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