1.

If the uncertainty in position of an electron is 4 x 10^(-10) m, the uncertainty in its momentum

Answer»

Answer:

5×10^-5 kgm/s

Explanation:

according \: to \: principle \: of \: <klux>UNCERTAINTY</klux> \: \\ ∆ x ∆ p \geqslant \frac{h}{4\pim}

where,

  • ∆x= uncertainty in position
  • ∆p= uncertainty in momentum
  • h= Planck's constant
  • m=MASS(here,mass of electron)

THEREFORE,

uncertainty in momentum,∆p is GIVEN by,

\alpha p = \frac{h}{ \alpha x4\pim} \\ = \frac{6.626 \times {10}^{ - 34} }{4 \times 3.14 \times 9.1 \times {10}^{ - 31} } \\ = 5 \times {10}^{ - 5}


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