1.

If the velocity of the particle is given byv=2+b?tThe dimensions of a & bare given as

Answer»

let us assumevrepresents velocity and t represents time in given expression then we may find dimensions ofa & bas following

L.H.S=v

=[L][T^(-1)]

R.H.S=at+bt^2

[at]=[bt^2](since only quantity of same dimensions are additive.)

[bt^2]=[bT^2]

since LHS should be equal to RHS

so

[bT^2]=[LT^(-1)]

b=LT^(-3)

sodimension of b will be [LT^(-3)]



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