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If the velocity of the particle is given byv= a + bt?The dimensions of a & bare given as |
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Answer» let us assumevrepresents velocity and t represents time in given expression then we may find dimensions ofa & bas following L.H.S=v =[L][T^(-1)] R.H.S=at+bt^2 [at]=[bt^2](since only quantity of same dimensions are additive.) [bt^2]=[bT^2] since LHS should be equal to RHS so [bT^2]=[LT^(-1)] b=LT^(-3) sodimension of b will be [LT^(-3)] |
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