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InterviewSolution
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If the wavelength of electromagnetic radiation is doubled, what happens to the energy of photon ? |
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Answer» Photon energy (E) =hv=`(hc)/(lambda)` `E prop (1)/(lambda)` Given `lambda_(1)=lambda, lambda_(2)=2lambda,E_(1)=E` `(E_(1))/(E_(2))=(lambda_(2))/(lambda_(1))` `(E)/(E_(2))=(2lambda)/(lambda)` `E_(2)=E//2` `therefore ` The energy of photon reduces to half to its initial value. |
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