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                                    Suppose that the electric field part of an electromagnetic wave in vacuum is E={(3.1 N/C) cos [(1.8 rad/m)y+{5.4`xx10^(6)` rad/s} t]} i. What is the wavelength `lambda` ? | 
                            
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Answer» Comparing the given question with equation `E=E_(0)cos (ky+omegat)` We have , `K=1.8` rad/m, `omega=5.4xx10^(8)` rad/s , `E_(0)=3.1` N/C `lambda=(2pi)/(k)=(2xx(22//7))/(1.8)=3.492~~3.5m`  | 
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