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In a plane electromagnetic wave, the electric field oscillates sinusoidally at a frequency of `2.0xx10^(10) Hz` and amplitude 48 V `m^(-1)`. What is the wavelength of the wave ? |
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Answer» Here, v=`2.0xx10^(10) Hz, E_(0)=48 Vm^(-1),C=3xx10^(8) m//s` wavelength of the wave , `lambda=(c)/(v)=(3xx10^(8))/(2.0xx10^(10))=1.5xx10^(-2)`m |
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