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If three resistors 15Ω, 3Ω and 4Ω each are connected in series, what is the effective resistance in the circuit? |
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Answer» Given: R1 =15Ω R2 = 3Ω R3 = 4Ω Effective resistance in series (Rs) = ? Rs = R1 + R2 + R3 Rs = 15 + 3 + 4 Rs = 22Ω The effective resistance in the circuit is 22Ω. |
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