1.

If Three resistors of 6Omega,9Omegaand21Omega are connected in series to a 12 V battery, find a] The total resistance of the circuit. b] The current flowing through the circuit. c] The potential difference across the 21Omega resistor.

Answer»

SOLUTION :a] TOTAL resistance = `6+9+21=36Omega`
b] Current = `V//R=12//36=0.33A`
c] P.D. ACROSS `21Omega=0.33xx21=7V`


Discussion

No Comment Found