If two networks have same graph with different type of elements between corresponding nodes, then?(a) \(\Sigma^{b}_{k=1}\)V1ki2k = 0, \(\Sigma^{b}_{k=1}\)V2ki1k = 0(b) \(\Sigma^{b}_{k=1}\)V1ki2k ≠ 0, \(\Sigma^{b}_{k=1}\)V2ki1k = 0(c) \(\Sigma^{b}_{k=1}\)V1ki2k = 0, \(\Sigma^{b}_{k=1}\)V2ki1k ≠ 0(d) \(\Sigma_{k=1}^{b}\)V1ki2k ≠ 0, \(\Sigma^{b}_{k=1}\)V2ki1k ≠ 0This question was addressed to me in exam.I'd like to ask this question from Tellegen’s theorem in portion Useful Theorems in Circuit Analysis of Network Theory

If two networks have same graph with different type of elements betwee

1.	If two networks have same graph with different type of elements between corresponding nodes, then?(a) \(\Sigma^{b}_{k=1}\)V1ki2k = 0, \(\Sigma^{b}_{k=1}\)V2ki1k = 0(b) \(\Sigma^{b}_{k=1}\)V1ki2k ≠ 0, \(\Sigma^{b}_{k=1}\)V2ki1k = 0(c) \(\Sigma^{b}_{k=1}\)V1ki2k = 0, \(\Sigma^{b}_{k=1}\)V2ki1k ≠ 0(d) \(\Sigma_{k=1}^{b}\)V1ki2k ≠ 0, \(\Sigma^{b}_{k=1}\)V2ki1k ≠ 0This question was addressed to me in exam.I'd like to ask this question from Tellegen’s theorem in portion Useful Theorems in Circuit Analysis of Network Theory
Answer» Correct choice is (a) \(\Sigma^{B}_{k=1}\)V1ki2k = 0, \(\Sigma^{b}_{k=1}\)V2ki1k = 0 To explain: If two networks have same graph with different TYPE of elements between corresponding NODES, then \(\Sigma^{b}_{k=1}\)V1ki2k = 0, \(\Sigma^{b}_{k=1}\)V2ki1k = 0.

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