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If two soap bubbles have radii in the ratio of 1:2 then the ratio of excess pressure will be? |
Answer» ≡QUESTION≡If two soap BUBBLES have radii in the ratio of 1:2 then what is the ratio of the excess pressure ? ║⊕ANSWER⊕║The excess pressure inside a soap bubble is denoted by the formula: Δ P = 4S / R Excess pressure is INVERSELY proportional to the radius for a GIVEN fluid. GIVEN R₁/R₂ = 1/2 p₁/p₂ = (4S/R₁) / (4S/R₂) p₁/p₂ = R₂/R₁ p₁/p₂ = 2/1 ∴ The ratio of excess pressure in the two soap bubbles will be in the ratio 2:1 (INVERSE of radius ratio). |
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