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If `V=(4)/(3)pir^(3)`, at what rate in cubic units is V increasing when r = 10 and `(dr)/(dt)` = 0.01?A. `pi`B. `4pi`C. `40pi`D. `4pi//3` |
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Answer» Correct Answer - B We have, `V=(4)/(3) pir^(3)` `implies(dV)/(dt)=4pir^(2)(dr)/(dt)` `implies (dV)/(dt)=4pixx100xx0.01 " "[because r = 10 and (dr)/(dt)=0.01]` `implies (dV)/(dt)=4pi` Hence, V is increasing at the rate of `4pi` cubic units per unit of time. |
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