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If `vec A= 3i + j +2k` and `vec B = 2i - 2j +4k` and `theta` is the angle between the two vectors, then `sin theta` is equal toA. `2/3`B. `2/(sqrt(3))`C. `2/(sqrt(7))`D. `2/(sqrt(13))` |
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Answer» Correct Answer - C `sin theta=(|vec(A)xxvec(B)|)/(AB)` |
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