If `[ vec axx vec b"" vec bxx vec c"" vec cxx vec a]=lambda[ vec a vec b vec c]^2`, then l is equal to(1) 2(2) 3(3) 0(4) 1

If `[ vec axx vec b"" vec bxx vec c"" vec cxx vec a]=lambda[ vec a vec

1.	If `[ vec axx vec b"" vec bxx vec c"" vec cxx vec a]=lambda[ vec a vec b vec c]^2`, then l is equal to(1) 2(2) 3(3) 0(4) 1
Answer» `[vec a xx vec b ; vec b xx vec c ; vec c xx vec a] = (vec a xx vec b)*[ (vec b xx vec c) xx (vec c xx vec a)]` `= (vec a xx vec b)[vec z xx (vec c xx vec a)]` `= (vec a xx vec b)[vec c(vec b xx vec c)]` Answer

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If `[ vec axx vec b"" vec bxx vec c"" vec cxx vec a]=lambda[ vec a vec b vec c]^2`, then l is equal to(1) 2(2) 3(3) 0(4) 1

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