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    				| 1. | If `vec r = 3 hati + 2 hatj - 5 hatk , vec a= 2 hati - hatj + hatk, vec b = hati + 3 hatj - 2hatk` `and vec c=2 hati + hatj - 3 hatk " such that " hat r = x vec a +y vec b + z vec c` thenA. x, y, z are in APB. x, y, z are in GPC. x, y, z are in HPD. `y, (x)/(2), z ` are in AP | 
| Answer» Correct Answer - D We have, `vec r = x vec a + y vec b + z vec c ` `rArr 3 hati + 2 hatj - 5 hatk =x (2 hati - hatj + hatk ) +y(hati + 3hatj -2 hatk ) + z( -2 hati + hatj - 3hatk)` `rArr 3= 2x+y-2z, 2= -x=3y + z, -5=x-2y-3z` `rArr x=3, y=1,z=2` Clearly, `x=y+z rArr y, (x)/(2),z` are in AP. | |