If `veca and vecb` are two vectors , then prove that `(vecaxxvecb)^(2)=|{:(veca.veca" ",veca.vecb),(vecb.veca" ",vecb.vecb):}|`

If `veca and vecb` are two vectors , then prove that `(vecaxxvecb)^(2)

1.	If `veca and vecb` are two vectors , then prove that `(vecaxxvecb)^(2)=\|{:(veca.veca" ",veca.vecb),(vecb.veca" ",vecb.vecb):}\|`
Answer» `(vecaxxvecb)^(2)=(ab sintheta.hatn)^(2)` `=a^(2)b^(2)sin^(2)theta` =`(veca.veca) (vecb.vecb)-(veca.vecb)^(2)` `=\|{:(veca.veca" ",veca.vecb),(vecb.veca" ",vecb.vecb):}\|`

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If `veca and vecb` are two vectors , then prove that `(vecaxxvecb)^(2)=|{:(veca.veca" ",veca.vecb),(vecb.veca" ",vecb.vecb):}|`

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