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If `veca and vecb` are unequal unit vectors such that `(veca - vecb) xx[ (vecb + veca) xx (2 veca + vecb)] = veca+vecb` then angle `theta " between " veca and vecb` is |
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Answer» Correct Answer - b,d `(vecaxxvecb)xx[(vecb+veca)xx (2veca+ vecb)] = vecb+veca` `or {(veca-vecb).(2veca+vecb) } (vecb +veca) ` `-{(veca-vecb). (vecb+veca)}(2veca + vecb)= vecb+veca` `or (2-veca.vecb- 1) (vecb +veca) = veca.vecb=1` `Rightarrow "either " vecb +veca =vec0 or 1 - veca.vecb=1` `Rightarrow "either " vecb = -veca or veca.vecb=0` `Rightarrow "either " theta= pi" "theta = pi//2` |
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