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If `veca=hati+hatj+2hatkandvecb=2hati+hatj+2hatk`, then find the unit vector in the direction of (i) `6vecb` (ii) 2veca-vecb` |
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Answer» Here, `veca=hatl+hatj+2hatkandvecb=2hati+hatj-2hatk` (i) since, `6vecb=12hatl+6hatj-12hatk` :. Unit vector in the direction of `6vecb=(6vecb)/(|6vecb|)` `=(12hati+6hatj-12hatk)/(sqrt12^(2)+6^(2)+12^(2))=(6(2hati+hatj-2hatk))/(sqrt324)` `=(6(2hati+hatj-2hatk))/(18)=(2hatj+hatj-2hatk)/(3)` (ii) Since, `2veca-vecb=2(hati+hatj+2hatk)-(2hati+hati-2hatk)` `=2hati+2hatj+4hatk-2hati-hatj+2hatk=hatj+6hatk` :. Unit vector in the direction of `2veca-vecb=(2veca-vecb)/(|2veca-vecb|)=(hatj+6hatk)/(sqrt1+36)=(1)/(sqrt37)(hatj+6hatk)` |
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