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If `veca = (hati + hatj +hatk), veca. vecb= 1 and vecaxxvecb = hatj -hatk , " then " vecb` isA. `hati - hatj + hatk`B. `2hati - hatk`C. `hati`D. `2hati` |
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Answer» Correct Answer - c `(veca xx vecb) xxveca = (veca.veca)vecb- (veca.vecb)veca` `(hatj-hatk)xx (hati +hatj +hatk) = (sqrt3)^(2)vecb - (hati +hatj +hatk)` `or 3vecb = 3hati or vecb = hati` |
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