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If `veca , vecb and vecc` are non- coplanar vectors and `veca xx vecc` is perpendicular to `veca xx (vecb xx vecc)` , then the value of `[ veca xx ( vecb xx vecc)] xx vecc` is equal toA. ` [veca vecb vecc] vecc`B. `[ veca vecb vecc] vecb`C. ` vec0`D. `[veca vecb vecc] veca` |
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Answer» Correct Answer - c Given that `veca, vecb and vecc` are non-coplanar, thus ` [veca vecb vecc] ne 0` again ` veca xx (vecb xx vecc) . (veca xx vecc) =0` `or (veca .vecc) =0` Hence, ` veca and vecc` are perpendicular, ` veca xx (vecb xx vecc) = (veca .vecc) vecb - (veca .vecb) vecc` ` or [veca xx (vecb xx vecc)] xx vecc = vec0` |
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