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If `veca,vecbandvecc` are unit vectors such that `veca+vecb+vecc=0`, then the value of `veca.vecb+vecb.vecc+vecc.veca` is |
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Answer» squaring `(veca+vecb+vecc)= vec0` we get `|veca|^(2)+|vecb|^(2)=|vecc|^(2)+2 veca.vecb+ 2vecb.vecc + 2vecc.veca=0` `2(veca.vecb+vecb.vecc+vecc.veca)=-3`n `veca.vecb+vecb.vecc+vecc.veca= -3/2` |
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