If `vecca xx (vec b xx vecc)` is perpendicular to `(veca xx vecb ) xx vecc`, we may haveA. `(veca.vecb)|vecb|^(2)= (veca.vecb)(vecb.vecc)`B. `veca.vecb=0`C. `veca.vecc=0`D. `vecb.vecc=0`

If `vecca xx (vec b xx vecc)` is perpendicular to `(veca xx vecb ) xx

1.	If `vecca xx (vec b xx vecc)` is perpendicular to `(veca xx vecb ) xx vecc`, we may haveA. `(veca.vecb)\|vecb\|^(2)= (veca.vecb)(vecb.vecc)`B. `veca.vecb=0`C. `veca.vecc=0`D. `vecb.vecc=0`
Answer» Correct Answer - a,c `vecaxx(vecbxxvecc)= (veca.vecc)vecb-(veca.vecb)vecb]and (vecaxx vecb) xxvecc=-(vecc. vecb) veca + (veca.vecc)vecb` we have been givn `(veca xx (vecbxx vecc)). ((vecaxxvecb)xxvecc)=0` ` or (veca . vecc)^(2)\|vecb\|^(2)- (veca.vecc)(vecb.vecc) (veca.vecb)` ` - (veca.vecb) (veca.vecc)(vecb.vecc)+ (veca.vecb)(vecb.vecc)(vecc.veca)=0` `or (veca.vecc)^(2)\|vecb\|^(2)= (veca.vecc)(veca.vecb)(vecb.vecc)` `or (veca.vecc)((veca.vecc)(vecb.vecb)- (veca.vecb) (vecb.vecc))=0` `veca.veca=0 or (veca.vecc) \|vecb\|^(2) = (veca.vecb)(vecb.vecc)`

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If `vecca xx (vec b xx vecc)` is perpendicular to `(veca xx vecb ) xx vecc`, we may haveA. `(veca.vecb)|vecb|^(2)= (veca.vecb)(vecb.vecc)`B. `veca.vecb=0`C. `veca.vecc=0`D. `vecb.vecc=0`

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