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If voltage across a conductor is (4+_0.1) and current is (2+ 0.1) Find resistance of conductor with error limit? |
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Answer» 2+_ 0.15 Ω MARK as brainliestExplanation:Here, V= 4 V , I = 2 A and Δ V = 0.1 V and Δ I = 0.1 A Now, R= V/I = 4/2 = 2 Ω for ERROR, Δ R /R = Δ V/ V + Δ I /I or, Δ R = R * (Δ V/ V + Δ I /I ) = 2 * (0.1 / 4 + 0.1 / 2) = 0.15 Ω So, RESISTANCE is 2+_ 0.15 Ω |
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