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If we plot a graph between log K and `(1)/(T)` by Arrhenius equation , the slope isA. `-(E_(a))/(R)`B. `+(E_(a))/(R)`C. `-(E_(a))/(2.303R)`D. `+(E_(a))/(2.303 R)` |
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Answer» Correct Answer - c ln k = ln `- (E_(a))/(RT)` is Arrhenius equation . Thus plots of ln k vs 1/T will give slope = `-E_(a)//RT` or `-E_(a)// 2.303R`. |
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