If women weighs 50 kg and the tips of the heel is 10mm2.What is the pr

1.	If women weighs 50 kg and the tips of the heel is 10mm2.What is the pressure exerted on the floor by her heel?
Answer» Explanation: Mass of the girl, m=50kg Diameter of the heel, d=1cm=0.01m Radius of the heel, R= 2 d =0.005m Area of the heel =πr 2 =π×(0.005) 2 =7.85×10 −5 m 2 FORCE EXERTED by the heel on the FLOOR: F=mg =50×9.8 =490N Pressure exerted by the heel on the floor: P= Area Force =490/(7.85×10 −5 )=6.24×10 6 N/m 2 Therefore, the pressure exerted by the heel on the HORIZONTAL floor is 6.24×10 6 N/m 2 .

If women weighs 50 kg and the tips of the heel is 10mm2.What is the pressure exerted on the floor by her heel?

Answer»

Explanation:

Mass of the girl, m=50kg

Diameter of the heel, d=1cm=0.01m

Radius of the heel, R=

=0.005m

Area of the heel =πr

=π×(0.005)

=7.85×10

−5

FORCE EXERTED by the heel on the FLOOR:

F=mg

=50×9.8

=490N

Pressure exerted by the heel on the floor:

Area

Force

=490/(7.85×10

−5

)=6.24×10

N/m

Therefore, the pressure exerted by the heel on the HORIZONTAL floor is 6.24×10

N/m

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If women weighs 50 kg and the tips of the heel is 10mm2.What is the pressure exerted on the floor by her heel?

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