If x, 2x+2, 3x+3 are in G.P, then 11x, 22x+22, 33x+33 form1. an A.P.2.

1.	If x, 2x+2, 3x+3 are in G.P, then 11x, 22x+22, 33x+33 form1. an A.P.2. a G.P.3. a constant sequence4. Neither A.P. nor a G.P.
Answer» Correct Answer - Option 2 : a G.P. Given: x , 2x + 2 & 3x + 3 are in G.P Concept used: G.P is the equence of numbers in which the ratio between consecutive terms is constant. Calculations: x, 2x + 2 & 3x + 3 are in G.P So, 2nd/1st = ( 2x + 2)/2 ⇒ 2nd/3rd = (3x+3)/(2x+2) Now, For, 11x, 22x + 22 , 33x + 33 (22x+22)/11x = (2x+2)/x (33x+33)/(22x+22) = (3x+3)/(2x+2) The ratio for both the series is coming the same, so both the series are in G.P. So, 11x, 22x+22 & 33x+33 series is in G.P. ∴ The correct choice is option 2.

If x, 2x+2, 3x+3 are in G.P, then 11x, 22x+22, 33x+33 form1. an A.P.2. a G.P.3. a constant sequence4. Neither A.P. nor a G.P.

Answer» Correct Answer - Option 2 : a G.P.

Given:

x , 2x + 2 & 3x + 3 are in G.P

Concept used:

G.P is the equence of numbers in which the ratio between consecutive terms is constant.

Calculations:

x, 2x + 2 & 3x + 3 are in G.P

So, 2nd/1st = ( 2x + 2)/2

⇒ 2nd/3rd = (3x+3)/(2x+2)

Now,

For, 11x, 22x + 22 , 33x + 33

(22x+22)/11x = (2x+2)/x

(33x+33)/(22x+22) = (3x+3)/(2x+2)

The ratio for both the series is coming the same, so both the series are in G.P.

So, 11x, 22x+22 & 33x+33 series is in G.P.

∴ The correct choice is option 2.