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if `x^3+ax+1=0 `and `x^4+ax^2+1=0` have common root then the exhaustive set of value of `a` isA. `a=2`B. `a=-2`C. `a=0`D. none of these |
Answer» Correct Answer - B We have `x^(3)+ax+1=0` or `x^(4)+ax^(2)+x=0`……………..i and `x^(4)+ax^(2)+1=0`……………ii From Eqs. (i) and (ii) we get `x-1=0` `impliesx=1` Which is a common root. `:.1+a+1=0` `impliesa=-2` |
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