InterviewSolution
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InterviewSolution
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If `{x}` and `[x]` represent fractional and integral part of x respectively, find the value of `[x]+sum_(r=1)^(2000)({x+r})/2000` |
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Answer» `[x]+sum_(r=1)^(2000)({x+r})/2000=[x]+sum_(r=1)^(2000)({x})/2000` [from property (i)] `=[x]+({x})/2000sum_(r=1)^(2000)1=[x]+({x})/2000xx2000=[x]+{x}=x` |
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