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If X and Y are two sets such that X has 40 elements, `X uuY`has 60 elements and `X nnY`has 10 elements, how many elements does Y have?

Answer» Here, `n(X)=40,n(X cupY)=60 and n(X capY)=10`
Therefore, `n(X)+n(Y)-n(X cap Y)=n(X cup Y)`
`rArr n(Y)=60+10-40`
`rArr n(Y)=30`
Therefore, number of elements in Y are `n(Y)=30`.


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