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If X and Y are two sets such that X has 40 elements, `X uuY`has 60 elements and `X nnY`has 10 elements, how many elements does Y have? |
Answer» Here, `n(X)=40,n(X cupY)=60 and n(X capY)=10` Therefore, `n(X)+n(Y)-n(X cap Y)=n(X cup Y)` `rArr n(Y)=60+10-40` `rArr n(Y)=30` Therefore, number of elements in Y are `n(Y)=30`. |
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