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If X follows a binomial distribution with parameters `n=8` and `p=1//2`, then `p(|X-4|le2)` equalsA. `(118)/(128)`B. `(119)/(128)`C. `(117)/(128)`D. none of these |
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Answer» Correct Answer - B We have, `P(|X-4|le2)=P(-2leX-4le 2)=P(2le X le 6)` `=P(X=2)+P(X=3)+P(X=4)+P(X=5)+P(X=6)` `=.^8C_2((1)/(2))^8=+.^8C_3((1)/(2))^8+.^8C_(4)((1)/(2))^8+.^8C_5((1)/(2))^8+.^8C_6((1)/(2))^8` `(1)/(2^8){28+56+70+56+28}=(238)/(2^8)=(119)/(128)` |
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