InterviewSolution
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InterviewSolution
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If `x in[-1/2,1] then sin^(-1)(sqrt(3)/(2)x-1/2sqrt(1-x^(2)))`A. `sin^(-1)1/2 -sin^(-1)x`B. `sin^(-1)x-(pi)/(6)`C. `sin^(-1)x+(pi)/(6)`D. none of these |
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Answer» Let `x=sin theta` then `-1/2lexle1rarr-1/2lesin theta le 1 rarr -(pi)/(6)le theta le (pi)/(2)` Now `sin^(-1)sqrt(3)/(2)x-1/2sqrt(1-x^(2))` `=sin^(-1){sin(theta-(pi)/(6))}` `=theta-(pi)/(6)` `=sin^(-1)x-(pi)/(6)` |
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