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If `x`is real, then `x//(x^2-5x+9)`lies between`-1a n d-1//11`b. `1a n d-1//11`c. `1a n d1//11`d. none of theseA. `-1 and -1//11`B. `1 and -1//11`C. `1 and 1//11`D. none of these |
Answer» Correct Answer - 2 Let `(x)/(x^(2) - 5x + 9) = y` or `yx^(2) - 5yx + 9y = x` or `yx^(2) - (5y + 1)x + 9y = 0` Now, x is real, so `D ge 0` `rArr (-(5y + 1))^(2) - 4 * y *(9y) ge 0` or `-11y^(2) + 10y + 1 ge 0` or `11y^(2) - 10y - 1 le 0` or `(11y + 1) (y - 1) le 0` or `-1/11 le y le 1` |
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