If x > y and 2xy/x2+y2 = cosθ, then sinθ = ……A) x2−y2/x2+y2B) x2+y2/x2−y2C) x2−y2/2xyD) 2xy/x2−y2

If x > y and 2xy/x2+y2 = cosθ, then sinθ = ……A) x2−y2/x2+y

1.	If x > y and 2xy/x2+y2 = cosθ, then sinθ = ……A) x2−y2/x2+y2B) x2+y2/x2−y2C) x2−y2/2xyD) 2xy/x2−y2
Answer» Correct option is: A) \(\frac{x^2-y^2}{x^2+y^2}\)