If `y=cos^(-1)(cos10)` then y is equal to

1.	If `y=cos^(-1)(cos10)` then y is equal to
Answer» We know , `cos^-1 in [0,pi).` So, we have to find a value from `0` to `pi`. Now, `cos(2npi-theta) = cos theta` For `n = 1, theta = 10`, `(2npi-theta) = (2pi -10) = (23.14 - 10) lt 0` For `n = 2, theta = 10`, `(2npi-theta) = (4pi -10) = (43.14 - 10) lt pi` So, it is in the range `[0,pi)`. `:. y = cos^-1(cos10) = cos^-1(cos(4pi-10)) = 4pi-10` `=> y = 4pi-10`

Discussion

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